tag:blogger.com,1999:blog-7947364481176430829.post3498527838162307570..comments2024-02-05T03:27:28.038-08:00Comments on C Programming Tutorials: Write a Program to print Product of Digits (eg. 212=2*1*2=4) of a given numberSagar P.http://www.blogger.com/profile/17634024193134198660noreply@blogger.comBlogger5125tag:blogger.com,1999:blog-7947364481176430829.post-13705818368452936412016-04-09T01:35:53.947-07:002016-04-09T01:35:53.947-07:00while r>9 why u usedwhile r>9 why u usedAnonymoushttps://www.blogger.com/profile/12641567400424618089noreply@blogger.comtag:blogger.com,1999:blog-7947364481176430829.post-84600943419109627442016-04-09T01:35:53.195-07:002016-04-09T01:35:53.195-07:00while r>9 why u usedwhile r>9 why u usedAnonymoushttps://www.blogger.com/profile/12641567400424618089noreply@blogger.comtag:blogger.com,1999:blog-7947364481176430829.post-27402278185454273252016-01-25T18:49:23.662-08:002016-01-25T18:49:23.662-08:00#include stdio.h>
int main()
{ int k,n,p,r,prod...#include stdio.h><br />int main()<br />{ int k,n,p,r,prod1=1,prod=1,sum=0,sum1=0,i=0,digit;<br />printf("\nEnter a non negative integer: ");<br /> scanf("%d",&n);<br /> if (n<10)<br /> {<br /> prod=n;<br /> sum=n;<br /> digit=1;<br /> }<br /> else<br /> {<br /> do<br /> {<br /> k=n%10;<br /> p=n-k;<br /> r=p/10;<br /> prod1=prod1*k;<br /> sum1=sum1+k;<br /> n=r;<br /> i++;<br /> }<br /> while(r>9);<br /> prod=prod1*r;<br /> sum=sum1+r;<br /> digit=i+1;<br /> }<br /> printf("\n\nproduct of digit: %d\n\nsum of digit: %d\n\nnumber of digit: %d\n",prod,sum,digit);<br /> return 0;<br />}<br />Ankit Kumarhttps://www.blogger.com/profile/11481177308250088762noreply@blogger.comtag:blogger.com,1999:blog-7947364481176430829.post-54508405080601199662016-01-25T18:47:56.215-08:002016-01-25T18:47:56.215-08:00This comment has been removed by the author.Ankit Kumarhttps://www.blogger.com/profile/11481177308250088762noreply@blogger.comtag:blogger.com,1999:blog-7947364481176430829.post-87801979865759166772016-01-25T18:45:11.927-08:002016-01-25T18:45:11.927-08:00This comment has been removed by the author.Ankit Kumarhttps://www.blogger.com/profile/11481177308250088762noreply@blogger.com